Lines Matching refs:K
342 |--X = 2^(K) * Y, 1 <= Y < 2. THUS, Y = 1.XXXXXXXX....XX IN BINARY.
344 |--THE IDEA IS THAT LOG(X) = K*LOG2 + LOG(Y)
345 |-- = K*LOG2 + LOG(F) + LOG(1 + (Y-F)/F).
351 |--GET K, Y, F, AND ADDRESS OF 1/F.
354 subil #0x3FFF,%d0 | ...THIS IS K
355 addl ADJK(%a6),%d0 | ...ADJUST K, ORIGINAL INPUT MAY BE DENORM.
357 fmovel %d0,%fp1 | ...CONVERT K TO FLOATING-POINT FORMAT
360 movel #0x3FFF0000,X(%a6) | ...X IS NOW Y, I.E. 2^(-K)*X
376 |--SUMMARY: FP0 IS Y-F, A0 IS ADDRESS OF 1/F, FP1 IS K
382 fmulx LOGOF2,%fp1 | ...GET K*LOG2 WHILE FP0 IS NOT READY
385 fmovex %fp1,KLOG2(%a6) | ...PUT K*LOG2 IN MEMORY, FREE FP1